

| Subject: | Re: Diesel Assembly Confusion. |
| From: | Dana Morphew |
| Date: | Sat, 16 Jun 2001 07:15:57 -0700 |
Mary Beth and Chris Geiser wrote: > > The top of the oil cooler is the side with little protrusions in a circle to > meet the bottom of the part from the engine. The bottom of the oil cooler > is the smooth side which comes in contact and is sealed by the rubber gasket > on the oil filter. Bentley doesn't specify a torque for that nut to hold it > on, so I made it comfortably tight. 25 Nm or about 18 ft.lbs. is the spec. > Never saw a gasket between the engine > part and the oil cooler part when I changed mine, but it might have stuck up > there and I didn't notice it either. The sealing ring Michael speaks of goes here. The Workshop Manual for the 1.9 diesels says: "coat contact surface to oil filter bracket outside sealing ring with AMV 188 100 02. I use Permatex Form-a-gasket here and it works well. -Dana- > Either way mine doesn't leak :) > Hope that helps, > Chris > > -----Original Message----- > From: Vanagon Mailing List [mailto:vanagon@gerry.vanagon.com]On Behalf > Of Rachel Cogent > Sent: Friday, June 15, 2001 9:47 PM > To: vanagon@GERRY.VANAGON.COM > Subject: Diesel Assembly Confusion. > > Please advise: > I am now assembling my '83 1.6D engine but have a snag. > There is a heat exchanger between the oil filter mount and the filter. > > Q: What exactly does this exchanger do? > > This metal box has two hoses going in and out and is held on by a large > threaded tube which the filter screws into at the lower end. > > Q: Which is the pressure end, this tube or the outside? > > The gasket set I have which is very complete does not have a sealer for the > top of the exchanger and I don't remember how it looked when I took it > apart. > > Q: Is this exchanger even standard equipment? > > It seems like there should be some copper rings or something for the metal > contacting parts but no such sizes are found. Does anyone have an exploded > picture of this assembly that can explain to me what to do? > > Thank you for any help here. > > Rachel
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