Peter,
Now you've made me feel guilty about not going out in the garage earlier and looking, but it's HOT out there! :) Just kidding, but it is hot everywhere in this part of Arizona.
There are 2 wires coming out of the shaft under the knob. The green one is attached to a screw on the base. The black one is attached with a screw under the knob. This screw also holds the copper piece which should be sort of "L" shaped, with one leg of the 'L' in a vertical position along the inner circumference of the knob. When you turn the knob, the copper piece makes contact with the screw on the base where the green wire is and completes the circuit to the pump.
You can't take it apart, it is glued or welded together and the wires just run down through the shaft to the bottom. My faucet was leaking from the bottom. I replaced it with a new one and then used a hacksaw to cut the old one open. There are o-rings and rubber balls an springs inside that make it work and keep it from leaking. Mine was leaking around the o-ring at the bottom of the shaft.
So, does the copper piece that fell out appear to be broken? Is the other half still attached under the knob? If so, maybe you can just make a new piece out of copper or brass, bent like the original was, drill a hole in it and attach it.
Hope this helps and good luck.
Jerry
  ----- Original Message ----- 
  From: Peter Johnson 
  To: vanagon@GERRY.VANAGON.COM 
  Sent: Thursday, July 12, 2001 12:45 PM
  Subject: faucet innards (not Farrah)

  Has anyone taken apart their pivoting spout faucet?  The little copper piece that is used to make contact with the screw under the knob has become detached on mine and I am not smart enough to figure out how to and where to put it back in.

  Thanks in advance

  Peter J
  85 Westy GL
  Willard, WA

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