Hmmm,

Doesn't look like the math quite works on that one...

Assuming you're raising the 32oz of water from 20�C to 100�C,
that's a rise of 80�C.

Now 32oz of water ~ 0.946kg
Specific heat of water = 4.19kJ/kg/�C (@4�C as I recall - it does
vary with temperature, but hey...)

So, to heat 0.946kg of water 80�C, you need
(0.946kg)*(4.19kJ/kg/�C)*(80�C) = 317.2kJ,
or 317,183 Joules. Given that 1 Joule=1watt*second, and you have 60
seconds to heat up,
you need 5.2864kJ/sec or 5,286.4 watts.

We're talking 5 kilowatts here, assuming 100% thermal efficiency,
and 100% effectiveness for the heat exchanger (basically impossible
without direct immersion of the heating elements). As my grandpa
used to say, you got a tough row to hoe on that inverter :-) Even
for 8oz of water, you're still talking 1320W.

Keith Hughes
'86 Westy Tiico, Marvin

> Date:    Mon, 20 May 2002 20:00:50 -0700
> From:    dave bowers <dave@SPARKPLUG.COM>
> Subject: Inverter question
>
> Hi Folks,
>
> My girlfriend is looking for a way to boil water quickly, as we travel on
> the road, in our 1986 Westy.
>
> She found a Rival 32 oz hot pot, which can boil water in 60 seconds!
>
> http://www.rivco.com/support_files/products/product_hotpots.htm
>
> We have a Sima 120v 300watt power inverter, and are trying to figure out,
> can our inverter handle an appliance like this. Currently, we have our
> inverter plugged in to our 12v outlet, and use it to charge our view cam
> cam- corder and Apple iBook laptop. I plan on hardwiring this to our Aux.
> battery some time soon.
>
> Sadly, this Rival hot pot does not list any information on how much draw
> (either amps or watts) it takes.
>
> Does anyone have any experience with an appliance like this? Can you
> recommend any alternative, if this is just too much draw?
>
> Any information would be great.
>
> Thanks much,
> dave bowers
> 1986 Westy
>