

| Subject: | Re: Curves (no Vanagon content) |
| From: | Stan Wilder |
| Date: | Wed, 29 Jan 2003 17:19:38 -0600 |
Contact Matthew Pollard he hangs with some smart guys ............ possibly some has rubbed off on him. Stan On Wed, 29 Jan 2003 16:22:45 -0600 Blake Thornton <thornton@MATH.UTAH.EDU> writes: > OK, having taught this stuff and having even done a fair amount of > work > studying "hyperbolic geometry" I thought I had to comment on the > answers > already given. > > - First, what is a "hyperbolic" curve. I know what a hyperbola is > (its a > conic section), but I'm not entirely sure what is meant by a > hyperbolic > curve. > > - A cantenary is (as someone pointed out) the curve formed by a > hanging > rope. the equation of such a curve is a fairly easy derivation. > It > should be easy to either just do the derivation or find it in either > a > calculus or differential equations book. > > - The method for drawing an ellipse was correct. An ellipse can be > shown > to have this property: "Ellipse is the set of points whose sum of > the > distance to the foci is a fixed constant." A hyperbola can be shown > to > have the similar property but you look at the difference of > distances. > > Well, I've got to run, but that is the summary. I don't know a > quick way > to draw a hyperbola, if thats what you want. > > Blake > > > > Hello Vanagon Troops!! > > > > I need your help. > > > > I need to draw a hyperbolic curve as a line drawing that will look > like > > a bowl. It has specific dimensions of 22" wide by 8 " deep. The > curve > > must be true for the dimensions. There is a way to do this with > string, > > pins, pencil, straight edge and triangle, but I don't know how. > Can > > anyone tell me how do do this??? > > > > Would appreciate it. > > > > Please reply off list. > > > > My thanks, > > > > John Rodgers > > 88 GL Driver > > > > ________________________________________________________________ Sign Up for Juno Platinum Internet Access Today Only $9.95 per month! Visit www.juno.com
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