

| Subject: | Re: 250 ft-lb torque wrench? |
| From: | John Rodgers |
| Date: | Fri, 28 Mar 2003 08:02:33 -0600 |
As long as the force applied is perpendicular to the lever, it doesn't matter. John Rodgers 88 GL Driver caryccc wrote: >I'm sure this is a silly question for those of you in the know, but why does >the lever need to be horizontal when measuring torque? The length of the >lever is the same at any angle, and the force applied will be perpendicular >to the lever, right? > >Cary > >----- Original Message ----- >From: George Goff <THX0001@AOL.COM> >To: <vanagon@GERRY.VANAGON.COM> >Sent: Thursday, March 27, 2003 9:02 AM >Subject: Re: 250 ft-lb torque wrench? > > > > >>In a message dated 3/26/03 4:24:18 PM, j_rodgers@CHARTER.NET writes: >> >><< The formula to calculate the FT/lbs is to multiply the length of the >> >> >arm > > >>times the force applied. >> >> >>As long as the force is tangent to the swing of the lever; the force is a >>vector whose magnitude can only be specified with its direction. That is >> >> >why > > >>a beam torque wrench has a floating handle. Having said that, if you are >>hanging a dead weight from a lever in order to apply a known torque, use a >>clevis between the weight and the lever, then stop when the lever is sorta >>horizontal. >> >>George >> >> >> > > >
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