Larry, on tightening the nut to 360 ft. Lbs....

Equation -
L = length of the cheater bar for your weight
F = Your weight
Ft-Lbs = torque value specified in this case 360 x ft x lbs

L = 360ft-lbs devided by your weight

Lets assume your weight to be 180 lbs -

Plug in the numbers

L = 360/180
L = 2

You need a 2 ft long cheater pipe extension to put over your pull hand
with the socket on it to torque to 360n ft lbs.

You can juggle those numbers. back and fourth but the relationship
remains the same. What length bar with what weight applied will give you
the 360 ft lbs of torque.

Really sounds like you need a new stub axle and associated parts.

Regards,

John Rodgers
88 GL Driver

Larry Chase wrote:

>Frank,
>
>I'd like to pick your brain a little on this topic.
>
>The RoadHaus has an ongoing problem with wheel bearings on the left
>rear.
>
>In 40,000 miles of continuous driving I have been thru 4 sets (Inner &
>Outer) bearings on that one wheel.
>
>After 1500 to 2000 miles there is significant play in the wheel (TOP TO
>BOTTOM AND SIDE TO SIDE).
>
>But I tend to run it for a couple thousand more miles before replacing.
>
>BTW ... Four different shops have looked at the problem and the
>collective diagnosis is to replace the axle hub assembly.
>
>The guess is that something must be out of round.
>
>Would you have any suggestions?
>
>Also on a related note ...
>
>"re-torque the nut to 360 ft. lbs.".
>
>I have never seen a shop that actually had a torque wrench that went as
>high as 360 ft lbs.
>
>They all torque as tight as they can .... Turn to the next slot and put
>the pin in (as per Bentley).
>
>- - -
>
>Date:    Sat, 21 Feb 2004 06:10:34 EST
>From:    Frank Condelli <RAlanen@AOL.COM>
>Subject: Re: Rear Axle Wiggle
>
>
>
>>>Clipped
>>>
>>>
>
>
>