

| Subject: | Re: Vanagon Math |
| From: | George Goff |
| Date: | Wed, 13 Oct 2004 22:14:30 EDT |
In a message dated 10/13/04 5:40:36 PM, inua@CHARTER.NET writes: << Given a vanagon with a 2.1L WBX engine, what is the top linear speed acheived by the piston when the engine is turning at 4000 rpm. >> It's the same as the instantaneous tangential velocity of the crank throw 90 degress before or after top dead center. V pmax = pi X stroke X 4000. Just plug in the stroke, whatever it is. George
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