

| Subject: | Re: How much fuel efficiency gained by shedding 300 lbs? |
| From: | Brandon Kolybaba |
| Date: | Thu, 18 Aug 2005 22:51:37 -0700 |
um... sure... nice 'to the man' argument there Jake. And the other is pretty piss poor too, "no, your wrong but I can't be bothered to explain why I think that" .... In that case why bother posting a reply at all ???? If you have succh a magic fomula do please share it with us. JM2C ----- Original Message ----- From: "Jake de Villiers" <crescentbeachguitar@TELUS.NET> To: <vanagon@GERRY.VANAGON.COM> Sent: Wednesday, August 17, 2005 4:57 PM Subject: Re: How much fuel efficiency gained by shedding 300 lbs? > Sorry Brandon. I know you are Canadian and all, but there IS one magic > formula that covers all cars. The value that changes is Cd, Cx in Europe, > and is derived from wind tunnel testing. If I had the time, or if I thought > it mattered, I would look it up in my old Car and Driver magazines, > but........ > The faster you go, the more wind resistance, the more fuel burned. I don't > quite understand the discussion anyway. I like poking along on two lane > roads, smelling the crops and stopping at will. I feel sorry for the drones > ripping down the highway at 85mph in their suv's, tinted windows and A/C > keeping the real world at a distance. I love the real world and relish > every chance to experience it anew. At 55mph and 25 mpg in my van. Seeya, > Jake > ----- Original Message ----- > From: "Brandon" <Brandon@CONCILIO.CA> > To: <vanagon@GERRY.VANAGON.COM> > Sent: Wednesday, August 17, 2005 2:05 PM > Subject: Re: How much fuel efficiency gained by shedding 300 lbs? > > > > so then the 2 conditions that must be met are: > > - same shape > > - same surface area > > > > correct? > > > > If so, I would argue that no 2 cars models have those in common and thus > > the wind resistance for each car is unique. As a result, no one magic > > formula can accurately account for how fuel inefficient all vehicles are > > unless it includes some kind of unique variable specific to that model of > > vehicle. > > > > as a side, I think what you meant to say was that the density of an object > > has no bearing on it's wind resistance. Which is true. However the higher > > the density the more energy it will take to change it's relative position > > i.e. - Accelerating from 0 to 65 MPH > > > > > > > I think he meant, a 6 ton flat brick has the same wind resistance as a > > > 200g flat brick. ;) > > > > > > On 8/17/05, Brandon <Brandon@concilio.ca> wrote: > > >> so by that logic a 1 pound Tear dropped shaped object has the same wind > > >> resistance as a 6 ton flat brick. > > >> > > >> note: our vans more closely resemble the brick :) > > >> > > >> > > >> > My goodness you guys, nobody is thinking, and I can't sit quietly any > > >> > longer! > > >> > > > >> > The mass of the vehicle does not change the wind resistance, or the > > >> MPG, > > >> > on > > >> > the highway. Stop and go or big hills is another story, but on flat > > >> ground > > >> > at steady speed the van could be 6 tons and you'd get the same MPG. > > >> > > > >> > At steady speed you are not accellerating the mass, you are only > > >> pushing > > >> > the > > >> > wind out of the way, so mass doesn't matter. > > >> > > > >> > John > > >> > Aircooled.Net Inc. > > >> > > > >> > > > >> > > > > > > > > >
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