

| Subject: | Re: Speed vs rpms w/ AT? |
| From: | John Bange |
| Date: | Sat, 17 Nov 2007 08:52:28 -0800 |
> I'd like to check my tach's accuracy. With the NH type automatic > transmission (1984 Vanagon), what the math to find what I should expect to > > read on the tach if I'm doing 60mph? Well, the 3rd gear ouput on the auto is 1:1, so that makes it a little easier. The differential in the final drive section is 4.09, so divide RPM by 4.09 to get the number of times per minute your real wheels are (ideally) rotating. Then reduce that by a little to account for the stupid non-locking torque converter---- I'd say a conservative 10% is about right for the far end. Now, just off the top of my head, "regular" vanagon tires are like 26" in diameter? So that's about 81 inches around (2 * pi * 13). There are 63360 inches per mile, 60 minutes per hour, so (conveniently) 60mph = 63360 inches/minute. 63360 divided by 81 gives you 782 wheel RPM, which multiplied times 4.09 for the differential gives you about 3200RPM ideally. Torque converter slippage will trend that a little higher, how much being determined by headwinds, hills, air resistance which increases at higher speeds, etc., but 10% makes a good high end guess, so divide by .9 for 3555 RPM. That means you should be indicating 3200-3500 RPM at 60mph. So the final formula for ideal MPH->RPM is: (MPH / 60 * 63360) / (pi * TireDiameter) * 4.09 The reverse, RPM->MPH is: ( RPM / 4.09 ) * (pi * TireDiameter) * 60 / 63360 The torque converter can really monkeywrench any attempt to get an accurate reading, but the ideal calculation at least gives you a place to start, particularly if you're considering a tire diameter change. Just copy-paste the appropriate formula into google's search box, replace MPH or RPM and TireDiameter with the appropriate values (google will fill in pi for you if you just type "pi"!) and click the search button. -- John Bange '90 Vanagon - "Geldsauger"
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