

| Subject: | Re: Water Cooler System Design Flaw Workaround? |
| From: | Tom Hargrave |
| Date: | Sun, 25 Apr 2010 19:41:48 -0500 |
-----Original Message----- From: Vanagon Mailing List [mailto:vanagon@GERRY.VANAGON.COM] On Behalf Of David Beierl Sent: Sunday, April 25, 2010 3:01 PM To: vanagon@GERRY.VANAGON.COM Subject: Re: Water Cooler System Design Flaw Workaround? At 01:22 PM 4/25/2010, Jake de Villiers wrote: >When approaching the long (15 - 30 minute) second and third gear grades >through Eastern Washington and Idaho you'd turn on the fan before the >rad got too hot. Ok, I see the idea. But do the numbers make sense? Lessee... at 75 horsepower output and 1/3 efficiency the engine's going to be putting out something like 200 kw of waste heat, or 3.4 kWh per minute. 18 quarts of 50/50 coolant weighs around 36 lb and has a specific heat capacity of roughly 0.85 BTU per lb per deg F at working temperature. So changing the entire coolant by 20F would get you 0.85 x 20 x 36 = ~600 BTU, about what a sedentary human throws off in an hour. 600 BTU = ~0.18 kWh. 3.4 kWh x 0.18 x 60 = ~32 So a twenty-degree change in the entire coolant would absorb the waste heat of the engine for about thirty two seconds. I think this is conservative since the coolant inside the engine won't be participating in this, and because 75 hp may be conservative for climbing a steep hill. Somebody check my numbers. If this number is anywhere near correct I don't think it's worth the hassle. Yours, David
Have something to add on this topic today? Revive this thread in the forum »