Oops, faulty math, really need some sleep.  Don't know how I changed RPM to pulses 
per second....

Distributor rotates at half crankshaft speed.... idle is 850 rpm.... half is 425 rpm... one Hall Effect signal
per crankshaft rotation ( or is that two per rotation...??).... nah, I'd better try to calculate this tomorrow!

James
Ottawa.....

> On Tue, Dec 3, 2013 at 4:41 PM, James <jk_eaton@hotmail.com> wrote:
> 
> >
> > It's fascinating to read your progress reports.  I predict that your
> > oscilloscope check on the output of the Hall sensor will produce a square
> > wave of about 5V, with an on period of about 50 microseconds, in a 2
> > millisecond period.  (Duty cycle of about 3% on a 400-450 Hz square wave
> > signal.)
> >
> >
> Uhmmm...wait a minute...a 2 millisecond period means 500 pulses per
> second...with two plugs firing with each crank rotation, thats 250
> rotations per second...which translates into 60 x 250 = 15,000 rpm...which
> means...that you've installed a Formula 1 engine into your Vanagon...Cool!!
> 
> 
> --
> Brett in Portland, OR
> "Albert" '82 VanaFox I4 Riviera