

| Subject: | Re: Time Delay LED Lighting Circuit |
| From: | Alistair Bell |
| Date: | Mon, 31 Jul 2017 15:24:52 -0700 |
Yeah I know Roy. I use pwm dimmers on the van. But what I guess I was trying to say is the voltage reduction dimming from the headlight switch rheostat didn't play that well with my home made dashled . Back to Neil's delayed off circuit. As it is what do you think will happen? Will the cap output voltage drop ? What I'd like to see is a circuit that delays off, full brightness held for a set time then a slow dim. It's so very elegant :-) Cheers Alistair > On Jul 31, 2017, at 3:05 PM, Roy Nicholl <RNicholl@NBNet.nb.ca> wrote: > > Apples and Pears ;-) > > Most incandescent dimming systems use phase control (AC world) or constant current reduction (CCR) (DC world). > > LEDs can also be dimmed via CCR (constant current reduction) which is the simpler method, but tends to have a minimum threshold around 10% below which output is unreliable. > > In AC applications (buildings) where drivers are being used Pulse-width modulation (PWM) - effectively switching the LED on/off thousands of times per second - produces a much better dimming effect (down to 1% brightness). > > >> On 31-Jul-2017, at 18:40, Alistair Bell <albell@SHAW.CA> wrote: >> >> Haven't found your basic led to dim very well david. Back in the day I made up led and resistor combo and fitted into the bulb holders for the dash lights. It dimmed to a certain point ( via headlight switch dimmer) then off. Not the same dimming as the incandescent. >> >> Alistair >> >>> On Jul 31, 2017, at 1:27 PM, David Beierl <dbeierl@ATTGLOBAL.NET> wrote: >>> >>> The resistor is to limit current through the LED which is a "constant >>> voltage" device like any diode. >>> >>> The LED will start dimming the instant power is removed. I would expect it >>> to dim rapidly at first and then more slowly. It might retain a minimal >>> glow for some time -- LEDs will visibly emit with microamps of current >>> running through them. >>> >>> LEDs dim perfectly well. If you put 2-watt LEDs in your instrument panel >>> they would dim similarly to the 2-watt incandescent lamps they replace -- >>> at high brightness. At low brightness they would still dim much more >>> slowly than the incandescents because the latter have to be red hot before >>> they begin to emit, which takes considerable current. But if you replace >>> your two watt panel lamps with 0.2 watt LEDs, the dimming rheostat meant to >>> work with a total of ~15 watts will have little effect on the 1.5 watt load. >>> >>> The formula for energy in watt-seconds (aka joules) stored in a capacitor >>> is Estored = Cfarads x Evolts^2 / 2. So your 4,000 uF cap charged to >>> twelve volts would in theory contain enough energy to run a two watt >>> festoon bulb for about three tenths of a second. In practice it would run >>> longer than that because it would only be using the full two watts at the >>> instant power was disconnected. >>> >>> The way the commercial circuits work is by using a timing circuit (no doubt >>> containing a timing capacitor) to operate a transistor that switches >>> battery current on and off. >>> >>> Yrs, >>> d >>> >>> >>> >>>> On Mon, Jul 31, 2017 at 3:45 PM, Neil N <musomuso@gmail.com> wrote: >>>> >>>> Yes. I too think the resistor is for voltage drop. Parts list >>>> specifies "an LED" so..... >>>> >>>> My sense is that voltage stored in the cap would naturally taper off >>>> but kind of moot if I used an LED(s). >>>> >>>> >
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