

| Subject: | Do the math! Re: Wheels, once and for all, Bill in Lake Tahoe. |
| From: | Ari Ollikainen |
| Date: | Sun, 1 Nov 1998 20:23:04 -0800 |
At 11:10 PM 11/1/98, Modl6971@aol.com wrote:
>In a message dated 11/1/98 5:55:39 PM Pacific Standard Time, Ari@OLTECO.com
>writes:
>
><<
> >Handling is great and the syncro looks like what it should look like.
> >It filled in the gap in the fenders. The van rides about 1.5 inches higher.
>
> Interesting...How does a 1 inch change in radius result in a 1.5inch
> change in ride height IF, as seen above, theres NO *increase* in
> tire section height?
>
> >>
>Well, let's see. I made a mistake, I went to a 16" rim viruses a 14," that's
>2 inch difference, so that's a 2 inch ride height difference. So there.
>Michael.
DUH...the 16" dimension is wheel DIAMETER, thus the ride height
increase over a 14" DIAMETER wheel will be 1/2 of the increase
in DIAMETER...or *1* inch.
The ride height is the distance measured from the center of HUB
to the ground and is composed of the wheel RADIUS + tire section
height.
OLTECO Ari Ollikainen
P.O. BOX 3688 Networking Technology and Architecture
Stanford, CA Ari@OLTECO.com
94309-3688 415.517.3519Have something to add on this topic today? Revive this thread in the forum »